import java.util.Scanner;
public class Test
{
public static void main(String []args)
{
String str1="青";
int num1=123;
Scanner scanner=new Scanner(System.in);
System.out.print("請輸入名字:");
String str=scanner.next(); //獲取字元串值
System.out.println("您輸入的名字是:"+str);
if(str1==str)
{
System.out.println("對不起,你不是青2");
}
else
{
System.out.print("請輸入密碼:");
int num=scanner.nextInt(); //獲取整數值
System.out.println("您輸入的密碼是:"+num);
if(num1==num)
{
System.out.println("歡迎你,青");
}
else
{
System.out.println("對不起,你不是青1");
}
}
}
}
2.java中如何輸入一個字元import java.util.*;
public class Test_01
{
public static void main(String[] args)throws Exception
{
System.out.println("請輸入一個字元");
char c=(char)System.in.read();
System.out.println(c);
}
}
擴展資料:
還可以輸入字元串,輸入字元串的方法
import java.io.*;
public class Test
{
public static void main(String[] args) throws IOException
{
BufferedReader buf = new BufferedReader (new InputStreamReader(System.in));
BufferedWriter buff = new BufferedWriter(new FileWriter("abc.txt"));
String str = buf.readLine();
while(!str.equals("exit"))
{
buff.write(str);
buff.newLine();
str = buf.readLine();
}
buf.close();
buff.close();
}
}
3.Java 寫一個輸入密碼的小程序已完成,複製粘貼即可。
import java.util.Scanner; public class YuGiOh { private static void checkPass ( String password ) { String regp = ".*[A-Z].*"; String rego = ".*[a-z].*"; String regq = ".*d.*"; String regs = ".*[`-!@#$%^&*()_+=[{}];:,.<>/?].*"; String regex = "^[a-zA-Zd`-!@#$%^&*()_+=[{}];:,.<>/?]{6,}$"; String result = ""; if (password.length () < 6) { result += "tt-contain at least six characters. Your password is only " + password.length () + " characters long.n"; } if (!password.matches (regp)) { result += "tt-contain at least one uppercase letter.n"; } if (!password.matches (rego)) { result += "tt-contain at least one lowercase letter.n"; } if (!password.matches (regq)) { result += "tt-contain at least one number.n"; } if (!password.matches (regs)) { result += "tt-contain at least one of the following special characters: `!@#$%^&*()_+=[{}];:,.<>/?n"; } else if (!password.matches (regex)) { result += "tt-not contain an invalid character. The valid special characters: `!@#$%^&*()_+=[{}];:,.<>/?n"; } if (!"".equals (result)) { System.out.println ("Your password must:n" + result); } else { System.out.println ("Your valid password is: " + password); } System.out.println (); } public static void main ( String[] args ) { Scanner scanner = new Scanner (System.in); while (true) { System.out.print ("Enter a valid password: "); String password = scanner.nextLine (); checkPass (password); } } }。
4.java中如何輸入一個字元暈,剛纔回答了你的問題,題目沒了……
實在不大想把代碼重新再寫一遍了。實際上很簡單。Scanner 是可以用的。讀進來的是字元串,比如說儲存在 str。
str.charAt(0); 就是第一個字元。括號裏的數字就是 index。把字元串就當數組看好了。
還有一個解決方案就直接用 char c = (char)new BufferedReader(new InputStreamReader(System.in)).read();
就可以讀取你輸入的第一個字元。
然後有了字元你就隨便處理好了。比如可以用 switch 語句:
switch (c) {
case 'A':
// do something
case 'B':
// do something
}
---------------------------------------
你初學者,我就把代碼再寫一遍吧:
import java.io.*;
public class Demo {
public static void main (String args[]) {
char c = 0;
try {
c = (char)new BufferedReader(new InputStreamReader(System.in)).read();
} catch (IOException ioe) {
System.exit(0);
}
switch (c) {
case 'A':
System.out.println("It is A.");
break;
case 'B':
System.out.println("It is B.");
break;
}
}
}
5.java如何輸入一個字元import java.util.Scanner; //引入Scanner類該類封裝了接收用戶輸入參數的一些操作
寫方法體
public static void main(String[] arg)
{
Scanner input=new Scanner(System.in); //定義一個從系統快取讀取數據的對偶
String str=scanner.next(); //從快取中讀出數據
System.out.println(str);
}